The equivalent capacitance of the combination shown in the figure between the indicated points is given by 
µF. then find the value of n.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(20µF)
Sol. Charge on capacitor is assume as according to reverse symmetry.
q 1 + q 2 = C eq V.....(i)
from loop AB EFA AB EFA ls
– 
= 0
⇒ 2q 2 – 3 q 1 = 0 .....(ii)
from loop ABCA AB CA l
– 
+ V = 0
⇒ 4V = 2q 1 + q 2 .....(iii)
from (i), (ii) and (iii) we get
q 1 + 
= C eq 
⇒ C eq = 
µF
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